Oxygen gas is at 22.4L and STP. What will be the volume of the oxygen of its temperature dropped by 5C
V2=T2V1T1V_2=\frac{T_2V_1}{T_1}V2=T1T2V1
V2=273×22.4278=22LV_2= \frac{273×22.4}{278}=22LV2=278273×22.4=22L
V2=22LV_2=22LV2=22L
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