A 5L gas is under a pressure 2 kPa at a temperature of 15C. What will the temperature be if the volume changes to 15L
V=vRT/p
R(constant gas temperature)=8.31J
T=V*p/vR
v=15l/22.4l/mol=0.67mol
T=15l*2kPa/0.67mol*8.31J=5.4C
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