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Answer to Question #199003 in General Chemistry for curey

Question #199003

485.0-mg sample containing MnO 2 was titrated with 75.00-mL of 0.1175 M FeSO4 solution. The excess iron was back titrated with 7.850-mL 0.0879 M K2Cr2O7. What is the percentage of MnO2 in the sample? (MW MnO2 = 86.94 g/mol)



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Expert's answer
2021-05-27T07:34:47-0400

Percentage of MnO2 in the sample=83.76%


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