Question

In an experiment, 2.62 g of iron react completely with 1.50g of sulfur. What is the empirical formula for the compound produced?

Answer 1

Moles of iron = $\frac{2.62}{56}=0.0468mol$

Moles of sulfur $=\frac{0.15}{32}= 0.0469$

Mole ratio of iron an sulfur is $0.0468:0.0469$

Which is almost $1:1$

The ratio of Fe to S is 1 : 1

Hence empirical formula for the compound produced is $FeS$