75 ml of 1.0 M lactic acid and 25 ml of 1.0 M sodium acetate. Ka of Lactic acid = 1.38 x10-4
pH=−log[H+]=−log(1.37×10−5)=4.86pH = - log[H+] = - log( 1.37 × 10-5 ) = 4.86pH=−log[H+]=−log(1.37×10−5)=4.86
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