Question

A quantity of gas occupies a volume of 548 mL at a temperature of 27 degrees C. What temperature (in Kelvin) will the volume of the gas be at 600 mL, assuming no change in pressure?

Answer 1

$\frac {V_1} {T_1} =\frac {V_2}{T_2}$

$T_2=\frac {300×600}{548}$

$T_2=328.5K$