1.The half-life of chromium-51 is 28 days. If the initial amount of chromium-51 is 133 mCi, how much chromium-51 is left in the body after 84 days?
N(t)=Nо(1/2)^t/1/2t
N(t)-remaining amount of substance
N(о)-Initial amount of the substance
N(t)=1/2*133mCi^84/1/2*28
N(t)=133*1/2^6
N(t)=133*1/64
N(t)=133/64
N(t)=2,078125 ~~ 2,08
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