Question #198690

the temperature of a gas started at 312 with a yolume of 4.5 L increased to 372 with a new volume of 1.2 what would the new pressure be if the initial pressure was 1.1 atm


1
Expert's answer
2021-05-26T07:07:20-0400

P1V1T1=P2V2T2\frac {P_1V_1} {T_1} =\frac {P_2 V_2}{T_2}


P2=1.1×4.5×372312×1.2P_2=\frac {1.1×4.5×372}{312×1.2}


P2=4.9atmP_2 =4.9atm


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