how would you prepare 2.0L of a 1.0M hci solution from 12.0m stock solution of hci?
The amount of the solute is constant during dilution. So the mole number of HCl is "2\u00d71.0=2 mole."
The volume of HCl stock is 2/12=0.167 L. So using 0.167 L stock solution and dilute to 2.0 L.
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