Question #198513

A student wants to measure the density of the unknown material using the displacement method.

He put 8.4 g of unknown material into the water initially at 45.4 ml, and the water level rose to 48.5 mL. What should be the correct density (g/cm3)of the unknown material from the following? 


1
Expert's answer
2021-05-26T07:12:42-0400

Weight of the unknown = 8.4 gm

Volume of water initially (V1)=45.5ml(V_1)=45.5 ml

Final volume of water (V2)=48.5ml(V_2)=48.5 ml

So the volume of the unknown material =V2V1=48.545.5=3ml=V_2-V_1=48.5-45.5=3ml


Now density:


density=massvolume=8.43=2.8g/mldensity=\dfrac{mass }{volume}=\dfrac{8.4}{3}=2.8 g/ml OR 2.8g/cm32.8g/cm^3


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