Question

A 25.00 mL sample of nitric acid was titrated with 0.6440 M strontium hydroxide. A total of 10.22 mL of the base was required to reach the equivalence point.

a) Write a balanced molecular equation for this reaction?

b) What was the concentration of the nitric acid?

Answer 1

$a)\ 2HNO_3 + Sr(OH)_2 \to Sr[(NO)_3]_2 + 2H_2O$

b)\Using, $\dfrac{​C_A​V_A​​}{C_B​V_B} =\dfrac{n_A}{n_B }$

$\dfrac{C_A ×25}{0.6440×10.22}=\dfrac21$

$3.79842 C_A= 2$

$C_A = 0.53M$