I have added 15 L of air to a balloon at sea level (1.0 atm). If i take the balloon with me to denver where the air pressure is 0.85 atm what will the new volume of the balloon be
P1V1=P2V2P_1V_1= P_2V_2P1V1=P2V2
V2=P1V1P2V_2= \frac{P_1V_1}{P_2}V2=P2P1V1
V2=1.0×150.85=17.64LV_2=\frac{ 1.0×15}{0.85}=17.64LV2=0.851.0×15=17.64L
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