I have added 15 L of air to a balloon at sea level (1.0 atm). If i take the balloon with me to denver where the air pressure is 0.85 atm what will the new volume of the balloon be
"P_1V_1= P_2V_2"
"V_2= \\frac{P_1V_1}{P_2}"
"V_2=\\frac{ 1.0\u00d715}{0.85}=17.64L"
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