A sample is observed to exert a pressure of 600 torr when confirmed to a 10.0 L vessels at 27 . C what will bbe its pressure in kPa when the gas is transfereed to an 8.0 L vessels at 300K?
P1=600 torrV1=10.0 LT1=27 C=27+273=300 KV2=8.0 LT2=300 KT1=T2=constantP1V1=P2V2P2=P1V1V2=600×10.08.0=750 torr=100 kPaP_1 = 600 \;torr \\ V_1 = 10.0 \;L \\ T_1 = 27 \;C = 27 + 273 = 300 \;K \\ V_2 = 8.0 \;L \\ T_2 = 300 \;K \\ T_1 = T_2 = constant \\ P_1V_1 = P_2V_2 \\ P_2 = \frac{P_1V_1}{V_2} \\ = \frac{600 \times 10.0}{8.0}= 750 \;torr = 100 \;kPaP1=600torrV1=10.0LT1=27C=27+273=300KV2=8.0LT2=300KT1=T2=constantP1V1=P2V2P2=V2P1V1=8.0600×10.0=750torr=100kPa
Answer: 100 kPa
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