Question #197098

What is the energy in joules of one mole of photons associated with red light of

wavelength 7.00 x 102 nm?

A. 1.71 x 105

J B. 12.4 kJ

C. 4.72 x 10-43 J

D. 256 kJ

E. 2.12 x 1042 J


1
Expert's answer
2021-05-25T07:50:16-0400

To calculate this energy per mole of photons we use the equation that relates the Planck's constant (h = 6.626 X 10-34 Js), the velocity of light (c = 2.998 X 108 m/s) , and wavelength [in meters] (λ = 7 X 10-7 m) as:


Ephoton=hcλE_{photon}=\frac{h\cdot c}{\lambda}


That was the energy per photon and we multiply it with Avogadro's constant (NA = 6.022 * 1023 mol-1) to have the energy per mole:


Emole=NAEphoton=NAhcλE_{mole} =N_A*E_{photon}=N_A\cdot\frac{h\cdot c}{\lambda}


Substituting all the constants and wavelength give us as result:


Emole=(6.626×1034Js)(2.998×108m/s)(6.022×1023mol1)7×107mE_{mole} =\frac{(6.626×10^{-34}\,J\bcancel{s})(2.998×10^{8}\,\bcancel{m}/\bcancel{s})(6.022×10^{23}\,mol^{-1})}{7×10^{-7}\,\bcancel{m}}


Emole=(6.626)(2.998)(6.022)7×1034+8+23+7Jmol1E_{mole} =\frac{(6.626)(2.998)(6.022)}{7}×10^{-34+8+23+7} \,J\,mol^{-1}


Emole=17.089×104Jmol1=1.71×105Jmol1E_{mole} =17.089×10^{4} \,J\,mol^{-1} = 1.71×10^{5} \,J\,mol^{-1}


In conclusion, option A (1.71 X 105 J) is the correct one.


Reference:

  • Castellan, G. W. (1983). Physical Chemistry. Ed.

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