what is the glucose that can be produced from a photosynthesis reaction that occurs using 10 mol CO2 using the equation 6CO2 + 6H2O --> C6H12O6 + 6O2?
v(C6H12O6)=v/6(CO2)=10mol/6=1.67mol (by the equation)
m(C6H12O6)=v(C6H12O6)*M(C6H12O6)
M(C6H12O6)=6*12g/mol+12*1g/mol+6*16g/mol=180g/mol (аccording to the periodic table)
m(C6H12O6)=1.67mol*180g/mol=300g
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