Question

What is the theoretical yield of vanadium that can be produced by the reaction of 40g of V2O5 with 40g of calcium based on the following chemical equation? - V2O5 + 5Ca -----> 2V + 5CaO

Answer 1

Moles of $V_2O_5= \frac{40}{181.88}=0.2199$ mol

Moles of $Ca= \frac{40}{40.078}=0.9980mol$

Hence Ca is the limiting reactant

$V_2O_5 + 5Ca ---> 2V + 5CaO$

From the equation,

Mass of $V_2O_5$ produced = $\frac{1}{5} ×0.9980×181.88 g/mol =36.30 g$