Answer to Question #196361 in General Chemistry for Osvaldo

Question #196361

Determine the molarity of 2.50 x 10^-6 kg of potassium phosphate in 500.0mL of solution

Expert's answer

n(K3PO4) = m/M = 2.5*10^-3g/212g/mol = 1.18*10^-5 mol

Molarity of K3PO4 = 1.18*10^-5 mol/0.5 L = 2.36*10^-5 M

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