Question

Two flasks are connected with a stopcock. Flask #1 has a volume of 2.5 L and contains oxygen gas at a pressure of 0.70 atm. Flask #2 has a volume of 3.8 L and contains hydrogen gas at a pressure of 1.25 atm. When the stopcock between the two flasks is opened and the gases are allowed to mix, what will the resulting pressure of the gas mixture be?

Answer 1

$P_T =\frac{ (P₁V₁ + P₂V₂) }{ (V₁ + V₂)}$

$P_T =\frac{ [(0.70 atm)(2.5 L) + (1.25 atm)(3.8 L)] }{(2.5 L + 3.8 L)}$

$P_T = 1.03 atm$