Question

If it takes 25 mL of 0.05 M HCl to neutralize 345 mL of NaOH solution, what is the concentration

of the NaOH solution?

Answer 1

Given, $M_1=0.05,V_1=25,V_2=345, M_2=?$

As we know-

$M_1V_1=M_2V_2\\[9pt]\Rightarrow M_2=\dfrac{0.05\times 25}{345}=0.003623M$