Answer to Question #195250 in General Chemistry for marisol

Question

How many grams of benzoic acid (C₆H₅COOH) are contained in a 125.0 mL solution at 0.26 M concentration?

Answer 1

We know that

Molarity = $\dfrac{w*1000}{m*V}$ .........................................Equation(1)

where, w = weight of the solute in the solution.

m = molar mass of the solute.

V = volume of the solution ( in mL).

It is given that, Molarity = 0.26 M

V = 125.0 mL

m = 122.12 gm

From Equation(1) we have,

0.26 = $\dfrac{w*1000}{122.12*125.0}$

w = $\dfrac{0.26*122.12*125.0}{1000}$

w = 3.9689 gm

3.9689 grams of benzoic acid (C₆H₅COOH) are contained in a 125.0 mL solution at 0.26 M concentration.