Question

Determine the [H3O + (aq)] of a solution with a pH of 3.45.

Answer 1

$pH = 3.45$

$-\log \{H_3O^+\}= 3.45$

$[H_3O^+] = 10^{-3.45}$

$[H_3O^+] = 0.0003548$

$[H_3O^+]= 3.55× 10^{-4} M$