Calculate the molarity of a solution when 600 grams of NaC2H3O2 are added to 2 L of solution
NaC2H3O2 have molar mass =
23 + 2×12 + 3 × 1 + 2×16
= 23 + 24 + 3 + 32
= 82 g / mol .
moles of NaC2H3O2
= 600 / 82
= 7.32 mol.
Molarity = moles / Volume .
= 7.32 / 2
= 3.66
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