What is the right ratio of chemicals for the given chemical equation?
__AgNO3 + __H2S --> __Ag2S+ __HNO3
When we balance the above mentioned chemical equation then the equation in the right stoichiometric coefficient is as follows:
"2AgNO_3+H_2S\\Rightarrow Ag_2S+2HNO_3"
By balancing the reaction we found that:
There are 2 moles of of Ag in left and 2 moles of of Ag in Right.
There are 2 moles of of in "N0_3" left and 2 moles of of "NO_3" in Right.
There are 2 moles of of "H_2" in left and 2 moles of of "H_2" in Right.
There are 1 mole of of S in left and 1 moles of of S in Right.
Hence this is the right ratio of the chemicals used in the equation..
Comments
Leave a comment