Question

What is the %-solution when 123 g Li₂SO₃ are dissolved in 450. mL of water? 

Answer 1

m/v% concentration is given as:

$=\frac{Mass of the solute(g)}{Volume of solvent(mL)}×100$

$=\frac{123g}{450mL}×100$

=27.34%

Therefore m/v% of given solution is 27.34%