Answer to Question #194743 in General Chemistry for Astalabista

Question

given the following reaction: 2 kclo₃ → 2 kcl + 3 o₂ how many grams of kclo₃ are needed to make 30.0 grams of kcl

Answer 1

Moles of Kcl $= \frac{30}{74.5513}=0.4052mol$

Moles of $KCl=$ moles of $KClO_3$

Mass of $KClO_3=0.4052×122.55=49.66grams$