Question #194740

If a 13.8 kg piece of aluminum with a specific heat of 0.129 J over grams degrees Celsius is heated from 30.0°C to 50.0°C what is the amount of energy absorbed by the aluminum


1
Expert's answer
2021-05-18T07:49:55-0400

∆T=50−30=20°C∆T = 50-30 = 20°C .


Energy absorbed =13.4×0.129×20=34.572= 13.4×0.129×20=34.572


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