Answer to Question #194714 in General Chemistry for Fjfkfkr

Question

Calculate the energy released, if a very hot metal of 100°c is dipped into water turns in to 30°c. The metal is 40 grams. Water’s specific heat is 4.18 J/g. C° (q=mCT)

Answer 1

Heat Relese = m. S . Deta T

Heat Relese = ( 40 ) × (4.18 ) × ( 100 -30 ).

Heat Relese = ( 40 × 4.18 × 70 ) j .

Heat Relese = 11704 j .

Heat Relese in kj = 11704 / 1000 kj .

Heat Relese in kj = 11.704 kj .