Use the reaction E + F <-> 2G and the equilibrium concentrations 0.60 mol/L for E, 0.80 mol/L for F, and 1.30 mol/L for G to calculate the equilibrium constant. E, F, and G are all gases.
"E + F\\ ^\\longrightarrow_\\longleftarrow\\ 2G"
At equilibrium;
"E =0.60\\ mol\/L \\\\\nF= 0.80\\ mol\/L\\\\\nG= 1.30\\ mol\/L"
"K_{eq} =\\dfrac{1.30\u00b2}{0.80\u00d7 0.60} = 3.521"
Comments
Leave a comment