Question #194668

Calculate the pH of an aqueous ammonia solution that has an OH-concentration of 3.9 × 103M. Is the solution more basic or acidic


Expert's answer

Solution.

[OH−]=3.9⋅103M;\begin{bmatrix} OH^- \\ \end{bmatrix}=3.9\sdot 10^3M;

[H+][OH−]=1⋅10−14  ⟹  [H+]=1⋅10−14[OH−];\begin{bmatrix} H^+ \\ \end{bmatrix}\begin{bmatrix} OH^- \\ \end{bmatrix}=1\sdot10^{-14}\implies \begin{bmatrix} H^+ \\ \end{bmatrix}=\dfrac{1\sdot10^{-14}}{\begin{bmatrix} OH^- \\ \end{bmatrix}};

[H+]=1⋅10−143.9⋅103=2.56⋅10−18;\begin{bmatrix} H^+ \\ \end{bmatrix}=\dfrac{1\sdot10^{-14}}{ 3.9\sdot10^3 }=2.56\sdot10^{-18};

pH=−log[H+]pH=-log\begin{bmatrix} H^+ \\ \end{bmatrix} ;

pH=−log(2.56⋅10−18)=17.59;pH=-log(2.56\sdot10^{-18})=17.59;

The solution is basic.

Answer: pH=17.59,pH=17.59,  the solution is basic.



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