Question

Calculate the heat of reaction: 2 NO(g)+O2(g)-->2NO2(g)

Answer 1

remaining information

1/2N₂ (g) + O₂ (g) → NO₂ (g), ΔH°A = 33.2 kJ .....(1)

1/2N₂ (g) + 1/2O₂ (g) → NO (g), ΔH°B = 90.2 kJ ....(2)

multiplying equation (1) by 2 and in equation 2 , first multiply by 2 and reverse it and then add both the equations

we get required equation

 2 NO(g)+O₂(g)-->2NO₂(g)

final =$(32.2\times2-90.2\times)kJ=114kJ$