Calculate the heat of reaction: 2 NO(g)+O2(g)-->2NO2(g)
remaining information
1/2N2 (g) + O2 (g) → NO2 (g), ΔH°A = 33.2 kJ .....(1)
1/2N2 (g) + 1/2O2 (g) → NO (g), ΔH°B = 90.2 kJ ....(2)
multiplying equation (1) by 2 and in equation 2 , first multiply by 2 and reverse it and then add both the equations
we get required equation
2 NO(g)+O2(g)-->2NO2(g)
final ="(32.2\\times2-90.2\\times)kJ=114kJ"
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