Question

the concentration of a reactant in a reaction decreases from 0.6 mole/L to 0.2 mole/L. in 10 seconds. Calculate the reaction rate.

Answer 1

$k=$ $2.303\over t$ $log$ $[A_°]\over[A]$

$=$ $2.303\over 10$ $log$ $0.6\over 0.2$

$=0.2303log 3$

$=1.099\times 10^{-1}$