Question

Consider the equation below and the masses of CuSO4 and Fe above to complete this page. 

 Fe (s) + CuSO4 (aq) → Cu (s) + FeSO4 (aq) 

Determine the theoretical yield of Cu in the reaction you will perform. Circle your answer. 

Fe - 2.005 g

CuSO4 - 11.343 g

Answer 1

Moles of Fe = $\frac {2.005}{58.845}= 0.034 mol$

Moles of CuSO4$= \frac {11.343}{159.609}= 0.071mol$

CuSO4 is the limiting reactant

Theoretical yield $= 0.071×63.546=4.511766$

Hence = 4.512 Grams