Answer to Question #193634 in General Chemistry for Shay

Question #193634

When making 50 mL of the 1.0M solution, he calculated that he needed 2.4g. Show the work that gives you that calculation.

Expert's answer

m=C*V*M

2.4g=1M*0.05l*Xg/mol

0.05x=2.4

x=48g/mol

m=1M*0.05l*48

m=2.4g

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