Answer to Question #193511 in General Chemistry for Josue D Aguilar-Ma

Question

What is the normality of 25.0 g of Al(OH)3 dissolved in 100.0 mL of water?

Answer 1

$Molarity= \dfrac{\dfrac{25}{78}}{0.1}$

= 3.20M

Hence, Normality= $n\times Molarity$

$3\times 3.20 = 9.60$