Question #193511

What is the normality of 25.0 g of Al(OH)3 dissolved in 100.0 mL of water?


1
Expert's answer
2021-05-17T04:16:16-0400

Molarity=25780.1Molarity= \dfrac{\dfrac{25}{78}}{0.1}


= 3.20M

Hence, Normality= n×Molarityn\times Molarity

3×3.20=9.603\times 3.20 = 9.60


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