Question

A gas is heated from 263.0 K to 298.0 K and the volume is increased from 24.0 liters to 35.0 liters by moving a large piston within a cylinder. If the original pressure were 1.00 atm, what would the final pressure be? 

Answer 1

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

$\frac{1.0×24.0}{263.0}=\frac{P_2×35.0}{298.0}$

$P_2=0.777atm$