A gas is heated from 263.0 K to 298.0 K and the volume is increased from 24.0 liters to 35.0 liters by moving a large piston within a cylinder. If the original pressure were 1.00 atm, what would the final pressure be?
P1V1T1=P2V2T2\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}T1P1V1=T2P2V2
1.0×24.0263.0=P2×35.0298.0\frac{1.0×24.0}{263.0}=\frac{P_2×35.0}{298.0}263.01.0×24.0=298.0P2×35.0
P2=0.777atmP_2=0.777atmP2=0.777atm
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