Question

Determine the pressure change when a constant volume of gas at 2.00 atm is heated from 30.0 °C to 40.0 °C.

Answer 1

1$^{st}$ condition:

$P_1=2atm$

$T_1=30^0C$ $=30+273.15=303.15K$

2$^{nd}$ condition:

Let $P_2=P_2$

$T_2=40^0C=40+273.15=313.15K$

Now from the gas equation we know that

$P\propto T$

Hence:

$\dfrac{P_1}{P_2}=\dfrac{T_1}{T_2}$

$P_2=2.067atm$

Now:

$\Delta P=P_2-P_1$

$\Delta P=2.067-2=0.067atm$