Question

A 112 kg man stands 551 m from a building with a mass of 25,500 kg. What was the force of gravity experienced by the man?

Answer 1

$F= \frac { −G×m×M} {r^2} ​$

Both the bodies with masses m and M exert same force F on each other.

The negative sign implies Attractive Nature of the force.

$F =- 6.67 ×\frac{ 112×25500}{551^2} ×10 ^{-11}$

F =$-6.275 ×10^{-11} N$