Answer to Question #192165 in General Chemistry for Lavante

Question #192165

A 112 kg man stands 551 m from a building with a mass of 25,500 kg. What was the force of gravity experienced by the man?


1
Expert's answer
2021-05-12T06:28:05-0400

"F= \n\n\\frac {\n\n \n\n\u2212G\u00d7m\u00d7M} {r^2}\n\n\u200b"

Both the bodies with masses m and M exert same force F on each other.


The negative sign implies Attractive Nature of the force.


"F =- 6.67 \u00d7\\frac{ 112\u00d725500}{551^2} \u00d710 ^{-11}"


F ="-6.275 \u00d710^{-11} N"


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