Answer to Question #191682 in General Chemistry for Jake

Question #191682

Aqueous hydrochloric acid HCl will react with solid sodium hydroxide NaOH to produce aqueous sodium chloride NaCl and liquid water H2O. Suppose 3.28 g of hydrochloric acid is mixed with 2.2 g of sodium hydroxide. Calculate the maximum mass of Sodium Chloride that could be produced by the chemical reaction. Round your answer to 2 significant digits.


1
Expert's answer
2021-05-11T05:57:29-0400

given reaction is-



HCl(aq)+NaOH(s)NaCl(aq)+H2O(l)HCl(aq)+NaOH(s)\to NaCl(aq)+H_2O(l)

moles of HCl taken =


=3.2836.5=0.090 mole=\frac{3.28}{36.5}=0.090\ mole

\frac{}{} moles of NaOH taken


=2.240=0.055 mole=\frac{2.2}{40}=0.055\ mole

So NaOH is the limiting reagent here

then

mass of Nacl formed = moles of Nacl multiplied by its molar mass

Moles of Nacl will be equal to moles of NaOH taken as they react in the ratio of 1:1.



=0.055×58.44=3.2 gm Nacl=0.055\times 58.44=3.2\ gm\ Nacl

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