Answer to Question #191393 in General Chemistry for Manal

Question

How much energy is required to raise the temperature of 250ml of water in a 500g kettle that is 100% iron from 20°C to 99°C?

Answer 1

q=m⋅c⋅ΔT

, where

q- heat absorbed/lost

m - the mass of the sample

c- the specific heat of the substance

ΔT- the change in temperature,

$\Delta T=99-20=79°c$

The specific heat of water is 4.18J/g⋅C

Mass= 250ml = 250g

$q = 250×4.18×79=82.555$