Question

Calculate the boiling point of a 0.44 m aqueous solution of AlCl3

Answer 1

Answer

$K_b = 0.512 \ ^oC/m$ .

 (MW of AlCl₃ is 133.339 g/mol).

$\Delta t_b =ik_bm\\ i=4 \\ \Delta t_b=4×0.512×0.44$

= 0.90112 this is the amount of change in temperature is required to get boiling temperature.