Question #190791

A coloured solution is placed within a spectrometer. At 554 nm the solution shows an absorbance of 0.69. Calculate the percentage of light that is being absorbed.


Expert's answer


Wavelength, λ=554nm,λ=554nm,Absorbance=0.69=0.69\lambda=554nm,λ=554nm, Absorbance = 0.69=0.69


The relation between Absorbance and transmittance is-


A=log(T100)0.69=log(T100)T1000=100.69A=-log(\dfrac{T}{100}) \\[9pt] 0.69=-log(\dfrac{T}{100}) \\[9pt] \dfrac{T}{1000}=10^{-0.69}


T=0.2041×100=20.41T=0.2041\times 100=20.41 %


Percentage of light absorbed


=100T=10020.41=79.59= 100-T=100-20.41=79.59 %




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