In November 2024
Answer to Question #190712 in General Chemistry for Kennedy Muyunda
a 0.010 mole sample of barium nitrate formed was heated until it had completely decomposed according to the following balanced equation.
2Ba(NO3)2 =2BaO + 4 NO2 + O2
. Using the ideal gass equation to calculate the total volume, cm3 of gaseous product obtained at 387K and 1.12×105 Pa.
Answer:-
2Ba(NO3)2 =2BaO + 4 NO2 + O2
Moles of barium nitrate= 0.010
P= 1.12×105 Pa
T=387K
Using Stoichiometry ee got
Total Volume of the gaseous products =107cm3
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#340153 on Dec 2023
Comments
how did u find 107cm3
2Ba(NO3)2 =2BaO + 4 NO2 + O2 Moles of barium nitrate= 0.010 P= 1.12×105 Pa T=387K Using Stoichiometry ee got Total Volume of the gaseous products =107cm3
How did you arrive at 107cm3
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