Question

What is the volume of 2.43 x 10^23 molecules of N2 gas at STP.

Answer 1

6.02×10²³ molecules = 1 mole 

2.43×10²³ molecules = 0.404 mole 

But PV = nRT 

where P = pressure of gas , V = volume 

n = no. of moles , T = Temperature, R = gas constant 

P=1atm

R=0.0821L/atm/mol/K

T=273K at STP

n=0.404moles

But V=$\frac{nRT}{P}$

=$\frac{0.404 mole ×0.0821L/atm/mol/K×273K}{1atm}$

V=9.05L