11. A gas storage tank as a volume of 4.5x105 m3 at 29 °C and 101.3 kPa. What is the new volume in cubic meters of the tank if the temperature drops to -15 °C and the pressure drops to 86 kPa?
Case 1:
P=101.3kpa,V=4.5×105m3,T=302KP=101.3kpa, V=4.5\times 10^5m^3, T=302KP=101.3kpa,V=4.5×105m3,T=302K
Using Ideal gas Equation-
PV=nRT101.3×105×4.5×105=nR×302⇒nR=1.509×1010 =(1)PV=nRT \\[9pt] 101.3\times 10^5\times 4.5\times 10^5=nR\times 302\\[9pt] \Rightarrow nR=1.509\times 10^{10} ~~~~~~=(1)PV=nRT101.3×105×4.5×105=nR×302⇒nR=1.509×1010 =(1)
Case 2:
P=86kpa,T=258K,P=86kpa,T=258K,P=86kpa,T=258K,
Using Ideal gas equation again-
PV=nRT86×105×V=1.509×1010×258V=389.4386×105=4.528×105m3PV=nRT \\[9pt] 86\times 10^5\times V=1.509\times 10^{10}\times 258\\[9pt]V=\dfrac{389.43}{86}\times 10^5 \\[9pt]=4.528\times 10^5 m^3PV=nRT86×105×V=1.509×1010×258V=86389.43×105=4.528×105m3
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment