A nonionizing solid dissolved in water change the freezing point to -2.79°C calculate its concentration.
Freezing point = 0 ºC – ΔTf
"-2.79 = 0 - \u0394T_f \\\\\n\n\u0394T_f = 2.79 \\\\\n\n\u0394T_f = K_f \\times m \\\\\n\n2.79 = 1.86 \\times m \\\\\n\nm = \\frac{2.79}{1.86} = 1.5 \\;M"
Answer: 1.5 M
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