Question

Copper sulphate solution is electolysed using platinum electrodes A. current of 0.193 amperes is passed for 3hrs. How many grams of copper are deposited? (cu = 63.5, F = 96500 coulombs)

Answer 1

Time = $2hrs. = 120 \times 60 = 7200s$

Current $= 0.193A$

Quantity of electricity $= 120 \times 0.193 = 60 \times 23.16$

96,500 deposits 63.5 gm of Cu.

60 x 23.2 will deposit $\dfrac{63.5 \times 60 \times 23.2 }{96500} = 0.457g$ of Copper.