Question

If 0.65 mole of N₂ occupies 18.0 L at a fixed particular temperature and pressure, how much volume would the gas occupy if the number of moles increased to 1.20?

PLEASE HELP

Answer 1

pV = nRT

T = constant

p = constant

R = gas constant

$n_1 = 0.65 \;mol \\ V_1 = 18.0 \;L \\ pV_1 = n_1RT \frac{V_1}{n_1} = \frac{RT}{p} \\ \frac{18.0}{0.65} = \frac{RT}{p} \\ 27.69 = \frac{RT}{p} \\ \frac{V_2}{n_2} = \frac{RT}{p} \\ \frac{V_2}{n_2} = 27.69 \\ \frac{V_2}{1.20} = 27.69 \\ V_2 = 1.20 \times 27.69 = 33.23 \;L$

Answer: 33.23 L