131-Iodine has a half life of 8.1 days. How much of a 1800 gram sample remains after 20 days?
325.0787381
N(t)= N(o)(1/2)^t/t1/2
Where N(t) = Remaining mass
N(o) =Original mass
T =Time
T1/2 = Half life
N(t) = 1800(1/2)^20/8.1
= 1800(0.5)^20/8.1
=325.0787381 grams
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