Question

How many grams is 5.97E24 molecules of C6H12O6 gas at STP?

Answer 1

No. of molecules of $C_6H_{12}O_6=5.97\times10^{24}$

so no. of moles of $C_6H_{12}O_6$ = $\dfrac{5.97\times10^{24}}{6.022\times10^{23}}=9.9=10$ moles(approximately)

Now weight of 10 moles of $C_6H_{12}O_6$ = $moles\times molar mass$

$=10\times180=1800gm$