C2H4 + 6F2 2CF4 + 4HF
Using the given equation
H2 + F2 2 HF ΔH= -573 KJ
2C + 2H2 C2H4 ΔH= + 52 KJ
CF4 C+ 2F2 ΔH= +680 KJ
∆H = -537 x2 kJ = -1074 kJ.
∆H = +680 x 4 kJ = 2720 kJ.
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